Exam questions · Maths · Algebra
Simplifying and Expanding Expressions
- 7 exam questions
- 17 marks
- 10 quick checks
-
1 Simplify [2 marks]
Simplify \(7p + 2q - 3p - 5q\).
Show answerHide answer
Model answer
\(7p - 3p = 4p\) and \(2q - 5q = -3q\), so the answer is \(4p - 3q\).
Mark scheme
- \(4p\) or \(-3q\) correct — M1
- \(4p - 3q\) — A1
-
2 Expand [3 marks]
Expand and simplify \(3(2x + 1) + 4(x - 3)\).
Show answerHide answer
Model answer
\(3(2x + 1) = 6x + 3\) and \(4(x - 3) = 4x - 12\). Adding gives \(10x - 9\).
Mark scheme
- \(6x + 3\) or \(4x - 12\) correct — M1
- \(6x + 3 + 4x - 12\) — M1
- \(10x - 9\) — A1
-
3 Simplify [2 marks]
Simplify (a) \(5b \times 2b^3\) [1 mark] (b) \(12m^5 \div 3m^2\) [1 mark]
Show answerHide answer
Model answer
(a) \(5 \times 2 = 10\) and \(b \times b^3 = b^4\), so \(10b^4\). (b) \(12 \div 3 = 4\) and \(m^5 \div m^2 = m^3\), so \(4m^3\).
Mark scheme
- (a) \(10b^4\) — B1
- (b) \(4m^3\) — B1
-
4 Expand [2 marks]
Expand and simplify \((x + 6)(x - 3)\).
Show answerHide answer
Model answer
\(x^2 - 3x + 6x - 18 = x^2 + 3x - 18\).
Mark scheme
- Three of the four terms correct, or \(x^2 - 3x + 6x - 18\) — M1
- \(x^2 + 3x - 18\) — A1
-
5 Expand [3 marks]
Expand and simplify \((3x - 1)(2x + 5)\).
Show answerHide answer
Model answer
\(6x^2 + 15x - 2x - 5 = 6x^2 + 13x - 5\).
Mark scheme
- At least three of the four terms correct — M1
- \(6x^2 + 15x - 2x - 5\) — M1
- \(6x^2 + 13x - 5\) — A1
-
6 Expand [2 marks]
Expand and simplify \((x - 4)^2\).
Show answerHide answer
Model answer
\((x - 4)(x - 4) = x^2 - 4x - 4x + 16 = x^2 - 8x + 16\).
Mark scheme
- \((x - 4)(x - 4)\) with three or four terms correct — M1
- \(x^2 - 8x + 16\) — A1
-
7 Show that [3 marks]
Show that \((x + 5)^2 - 25 \equiv x(x + 10)\).
Show answerHide answer
Model answer
\((x + 5)^2 = x^2 + 10x + 25\). Subtracting 25 gives \(x^2 + 10x\), which is \(x(x + 10)\), as required.
Mark scheme
- \((x + 5)(x + 5)\) or \(x^2 + 5x + 5x + 25\) — M1
- \(x^2 + 10x + 25 - 25\) or \(x^2 + 10x\) — M1
- \(x(x + 10)\) with a conclusion — Q1
Quick check
-
1
Expand and simplify \((x + 3)(x - 3)\).
Show answerHide answer
D: \(x^2 - 9\)
\(x^2 - 3x + 3x - 9 = x^2 - 9\), because the middle terms cancel.
-
2
\(n\) is an integer. Which of these expressions is always an odd number?
Show answerHide answer
A: \(2n + 1\)
\(2n\) is always even, so \(2n + 1\) is always odd.
-
3
Simplify \(4x + 3y - x + 2y\).
Show answerHide answer
A: \(3x + 5y\)
Collect the \(x\) terms: \(4x - x = 3x\). Collect the \(y\) terms: \(3y + 2y = 5y\).
-
4
Simplify \(3x \times 4x^2\).
Show answerHide answer
A: \(12x^3\)
Multiply the numbers (\(3 \times 4 = 12\)) and add the powers (\(x^1 \times x^2 = x^3\)).
-
5
Expand \(3(2x - 5)\).
Show answerHide answer
D: \(6x - 15\)
Multiply both terms inside by 3: \(3 \times 2x = 6x\) and \(3 \times (-5) = -15\).
-
6
Expand \(-2(x - 4)\).
Show answerHide answer
D: \(-2x + 8\)
\(-2 \times x = -2x\) and \(-2 \times (-4) = +8\), so the answer is \(-2x + 8\).
-
7
Expand and simplify \((x + 3)(x + 5)\).
Show answerHide answer
D: \(x^2 + 8x + 15\)
\(x^2 + 5x + 3x + 15 = x^2 + 8x + 15\).
-
8
Expand and simplify \((x - 4)^2\).
Show answerHide answer
C: \(x^2 - 8x + 16\)
\((x - 4)(x - 4) = x^2 - 4x - 4x + 16 = x^2 - 8x + 16\).
-
9
Which of these is an identity, true for every value of \(x\)?
Show answerHide answer
C: \(2(x + 3) \equiv 2x + 6\)
Expanding the bracket shows \(2(x + 3)\) is always equal to \(2x + 6\). The others are true only for certain values.
-
10
Simplify \((2x^3)^2\).
Show answerHide answer
C: \(4x^6\)
Square the 2 to get 4 and multiply the powers: \((x^3)^2 = x^6\).