Exam questions · Maths
Standard Form and Accuracy
- 30 exam questions
- 75 marks
- 45 quick checks
Standard Form
Just this lesson-
1 Write [2 marks]
Write 7 300 000 in standard form. [2 marks]
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Model answer
The decimal point moves 6 places left, so \(7.3 \times 10^6\).
Mark scheme
- 7.3 seen — M1
- \(7.3 \times 10^6\) — A1
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2 Write [2 marks]
Write \(4.1 \times 10^{-2}\) as an ordinary number. [2 marks]
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Model answer
Move the decimal point 2 places right: 0.041.
Mark scheme
- Moves the decimal point 2 places — M1
- 0.041 — A1
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3 Explain [2 marks]
Which is bigger, \(6 \times 10^{-3}\) or \(2 \times 10^{-2}\)? Give a reason. [2 marks]
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Model answer
\(2 \times 10^{-2} = 0.02\) and \(6 \times 10^{-3} = 0.006\), so \(2 \times 10^{-2}\) is bigger, because \(-2\) is greater than \(-3\).
Mark scheme
- \(2 \times 10^{-2}\) — B1
- A correct reason — Q1
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4 Write [3 marks]
(a) Write 0.00086 in standard form. [2 marks] (b) Write \(2.5 \times 10^4\) as an ordinary number. [1 mark]
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Model answer
(a) The point moves 4 places right, so \(8.6 \times 10^{-4}\). (b) 25 000.
Mark scheme
- (a) 8.6 seen — M1
- (a) \(8.6 \times 10^{-4}\) — A1
- (b) 25 000 — B1
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5 Write [2 marks]
Write \(0.8 \times 10^5\) in standard form. [2 marks]
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Model answer
\(0.8 = 8 \times 10^{-1}\), so \(0.8 \times 10^5 = 8 \times 10^4\).
Mark scheme
- \(80\,000\) or \(8 \times 10^{-1}\) seen — M1
- \(8 \times 10^4\) — A1
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6 Work out [3 marks]
A virus is 0.00000012 m long. [3 marks] (a) Write this length in standard form. [2 marks] (b) A bacterium is \(3 \times 10^{-6}\) m long. Which is longer, the virus or the bacterium? [1 mark]
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Model answer
(a) The point moves 7 places right, so \(1.2 \times 10^{-7}\) m. (b) \(3 \times 10^{-6}\) is bigger than \(1.2 \times 10^{-7}\), so the bacterium is longer.
Mark scheme
- (a) 1.2 seen — M1
- (a) \(1.2 \times 10^{-7}\) — A1
- (b) The bacterium — B1
Quick check
-
1
What is 45 000 in standard form?
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B: \(4.5 \times 10^4\)
The decimal point moves 4 places left to give 4.5.
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2
What is \(3.2 \times 10^{-3}\) as an ordinary number?
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A: 0.0032
A power of \(-3\) moves the decimal point 3 places to the right of the 3, giving 0.0032.
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3
Which of these is in standard form?
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D: \(6.2 \times 10^5\)
The first part must be at least 1 and less than 10, and the base must be 10.
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4
What is 0.00045 in standard form?
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C: \(4.5 \times 10^{-4}\)
The decimal point moves 4 places right, so the power is \(-4\).
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5
What is \(45 \times 10^3\) in standard form?
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B: \(4.5 \times 10^4\)
\(45 = 4.5 \times 10\), so \(45 \times 10^3 = 4.5 \times 10^4\).
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6
Which is bigger, \(2 \times 10^7\) or \(9 \times 10^6\)?
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A: \(2 \times 10^7\)
\(2 \times 10^7 = 20\,000\,000\) and \(9 \times 10^6 = 9\,000\,000\).
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7
The distance to the Sun is about 150 million km. What is this in standard form?
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D: \(1.5 \times 10^8\) km
150 million is 150 000 000, so the point moves 8 places to give 1.5.
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8
What is \(3.2 \times 10^5\) as an ordinary number?
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C: 320 000
Move the decimal point 5 places right.
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9
Which is smaller, \(5 \times 10^{-3}\) or \(8 \times 10^{-5}\)?
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B: \(8 \times 10^{-5}\)
\(5 \times 10^{-3} = 0.005\) and \(8 \times 10^{-5} = 0.00008\).
Calculating with Standard Form
Just this lesson-
1 Work out [2 marks]
Work out \((3 \times 10^2) \times (2 \times 10^5)\). Give your answer in standard form. [2 marks]
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Model answer
\(3 \times 2 = 6\) and \(10^2 \times 10^5 = 10^7\), so \(6 \times 10^7\).
Mark scheme
- \(3 \times 2\) or \(10^7\) — M1
- \(6 \times 10^7\) — A1
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2 Work out [2 marks]
Work out \((8 \times 10^9) \div (4 \times 10^6)\). Give your answer in standard form. [2 marks]
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Model answer
\(8 \div 4 = 2\) and \(10^9 \div 10^6 = 10^3\), so \(2 \times 10^3\).
Mark scheme
- \(8 \div 4\) or \(10^3\) — M1
- \(2 \times 10^3\) — A1
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3 Work out [3 marks]
Work out \((5 \times 10^4) \times (6 \times 10^3)\). Give your answer in standard form. [3 marks]
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Model answer
\(5 \times 6 = 30\) and \(10^4 \times 10^3 = 10^7\), giving \(30 \times 10^7 = 3 \times 10^8\).
Mark scheme
- \(30 \times 10^7\) — M1
- Adjusts to standard form — M1
- \(3 \times 10^8\) — A1
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4 Work out [3 marks]
Work out \(4 \times 10^5 + 6 \times 10^4\). Give your answer in standard form. [3 marks]
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Model answer
\(400\,000 + 60\,000 = 460\,000 = 4.6 \times 10^5\).
Mark scheme
- Same power or ordinary numbers — M1
- 460 000 or \(4.6 \times 10^5\) seen — M1
- \(4.6 \times 10^5\) — A1
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5 Work out [3 marks]
A grain of sand is \(2 \times 10^{-3}\) m wide. \(5 \times 10^6\) grains are put in a line, side by side. Work out the length of the line. Give your answer in standard form. [3 marks]
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Model answer
\((5 \times 10^6) \times (2 \times 10^{-3}) = 10 \times 10^3 = 1 \times 10^4\) m.
Mark scheme
- \(5 \times 2 = 10\) or \(10^6 \times 10^{-3} = 10^3\) — M1
- \(10 \times 10^3\) — M1
- \(1 \times 10^4\) m — A1
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6 Work out [3 marks]
Work out \((9 \times 10^{-3}) \div (3 \times 10^{-5})\). Give your answer in standard form. [3 marks]
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Model answer
\(9 \div 3 = 3\) and \(10^{-3} \div 10^{-5} = 10^{-3 - (-5)} = 10^2\), so the answer is \(3 \times 10^2\).
Mark scheme
- \(9 \div 3 = 3\) — M1
- \(10^2\) seen — M1
- \(3 \times 10^2\) — A1
Quick check
-
1
What is \((2 \times 10^3) \times (3 \times 10^4)\)?
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C: \(6 \times 10^7\)
Multiply \(2 \times 3 = 6\) and add the powers, \(3 + 4 = 7\).
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2
What is \((6 \times 10^8) \div (3 \times 10^3)\)?
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B: \(2 \times 10^5\)
Divide \(6 \div 3 = 2\) and subtract the powers, \(8 - 3 = 5\).
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3
What is \((4 \times 10^5) \times (5 \times 10^3)\) in standard form?
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A: \(2 \times 10^9\)
\(4 \times 5 = 20\) and \(10^5 \times 10^3 = 10^8\), so \(20 \times 10^8 = 2 \times 10^9\).
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4
What is \(3 \times 10^4 + 5 \times 10^3\) in standard form?
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D: \(3.5 \times 10^4\)
\(30\,000 + 5000 = 35\,000 = 3.5 \times 10^4\).
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5
What is \(6.2 \times 10^5 - 3 \times 10^4\) in standard form?
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C: \(5.9 \times 10^5\)
\(620\,000 - 30\,000 = 590\,000 = 5.9 \times 10^5\).
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6
What is \(10^7 \div 10^{-2}\)?
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B: \(10^9\)
Subtract the powers: \(7 - (-2) = 9\).
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7
What is \((4 \times 10^{-3}) \times (2 \times 10^{-2})\)?
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A: \(8 \times 10^{-5}\)
Multiply \(4 \times 2 = 8\) and add the powers, \(-3 + (-2) = -5\).
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8
What is \((3.6 \times 10^7) \div (1.2 \times 10^{-2})\)?
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D: \(3 \times 10^9\)
\(3.6 \div 1.2 = 3\) and \(10^7 \div 10^{-2} = 10^9\).
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9
\(5 \times 10^8\) bacteria, each \(2 \times 10^{-6}\) m long, are placed end to end. How long is the line?
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C: \(1 \times 10^3\) m
\(5 \times 2 = 10\) and \(10^8 \times 10^{-6} = 10^2\), so \(10 \times 10^2 = 1 \times 10^3\).
Rounding and Estimating
Just this lesson-
1 Write [2 marks]
Write 0.0764 (a) correct to 2 decimal places, (b) correct to 2 significant figures. [2 marks]
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Model answer
(a) The next digit is 6, so 0.08. (b) The first two significant figures are 7 and 6, and the next digit 4 rounds down: 0.076.
Mark scheme
- (a) 0.08 — B1
- (b) 0.076 — B1
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2 Write [2 marks]
Write 58 700 correct to 1 significant figure. [2 marks]
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Model answer
The first figure is 5, and the next digit 8 rounds it up to 6, with zeros to hold the place: 60 000.
Mark scheme
- 6 seen — M1
- 60 000 — A1
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3 Estimate [3 marks]
Work out an estimate for \(\dfrac{6.1 \times 19.7}{0.41}\). [3 marks]
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Model answer
\(\dfrac{6 \times 20}{0.4} = \dfrac{120}{0.4} = 300\).
Mark scheme
- Rounds to 6, 20 and 0.4 — M1
- \(\dfrac{6 \times 20}{0.4}\) — M1
- 300 — A1
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4 Estimate [3 marks]
Work out an estimate for \(\dfrac{298 \times 0.52}{5.1}\). [3 marks]
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Model answer
\(\dfrac{300 \times 0.5}{5} = \dfrac{150}{5} = 30\).
Mark scheme
- Rounds to 300, 0.5 and 5 — M1
- \(\dfrac{300 \times 0.5}{5}\) — M1
- 30 — A1
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5 Write [2 marks]
Write 3.996 correct to 2 decimal places. [2 marks]
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Model answer
The next digit is 6, so round the 9 up, which carries: 4.00.
Mark scheme
- 4 or 4.0 seen — M1
- 4.00 — A1
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6 Estimate [3 marks]
(a) Work out an estimate for \(5.2 \times 8.3\). [2 marks] (b) Is your estimate bigger or smaller than the exact value? Give a reason. [1 mark]
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Model answer
(a) \(5 \times 8 = 40\). (b) Both numbers were rounded down, so the estimate is smaller than the exact value.
Mark scheme
- (a) 5 and 8 seen — M1
- (a) 40 — A1
- (b) Smaller, because both were rounded down — Q1
Quick check
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1
What is 4.678 to 1 decimal place?
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D: 4.7
The next digit is 7, so round up.
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2
What is 6482 to 2 significant figures?
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C: 6500
The first two figures are 6 and 4, and the next digit 8 rounds the 4 up to 5, with zeros to hold the place.
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3
What is 0.004567 to 2 significant figures?
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B: 0.0046
The first significant figure is the 4, and the next digit 6 rounds the 5 up.
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4
What is 83.7 to the nearest 10?
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A: 80
83.7 is closer to 80 than to 90.
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5
What is the best estimate for \(\dfrac{4.97 \times 20.1}{0.49}\)?
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D: 200
\(\dfrac{5 \times 20}{0.5} = \dfrac{100}{0.5} = 200\).
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6
To estimate a calculation, to how many significant figures do you round each number?
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C: 1
One significant figure keeps the arithmetic easy.
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7
The bottom of a fraction is rounded up. What happens to the estimate?
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B: It is smaller than the true value
A bigger number on the bottom makes the fraction smaller.
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8
What is the best estimate for \(\dfrac{39.8 \times 5.1}{0.21}\)?
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A: 1000
\(\dfrac{40 \times 5}{0.2} = \dfrac{200}{0.2} = 1000\).
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9
What is 0.0305 to 2 significant figures?
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D: 0.031
The significant figures are 3 and 0. The next digit is 5, so round the 0 up to 1.
Error Intervals and Bounds
Just this lesson-
1 Write down [2 marks]
\(x = 40\) correct to the nearest 10. Write down the error interval for \(x\). [2 marks]
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Model answer
Half of 10 is 5, so \(35 \leq x < 45\).
Mark scheme
- 35 and 45 seen — M1
- \(35 \leq x < 45\) — A1
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2 Write down [2 marks]
\(x = 0.4\) correct to 1 significant figure. Write down the error interval for \(x\). [2 marks]
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Model answer
The unit is 0.1, so half is 0.05, and \(0.35 \leq x < 0.45\).
Mark scheme
- 0.35 and 0.45 seen — M1
- \(0.35 \leq x < 0.45\) — A1
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3 Write down [2 marks]
The number \(n\) is 5 after it has been truncated to an integer. Write down the error interval for \(n\). [2 marks]
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Model answer
\(5 \leq n < 6\).
Mark scheme
- 5 and 6 seen — M1
- \(5 \leq n < 6\) — A1
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4 Work out [3 marks]
\(a = 9\) cm and \(b = 4\) cm, each correct to the nearest centimetre. Work out the upper bound of \(a - b\). [3 marks]
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Model answer
The upper bound of \(a\) is 9.5 and the lower bound of \(b\) is 3.5, so the upper bound of \(a - b\) is \(9.5 - 3.5 = 6\).
Mark scheme
- 9.5 or 3.5 seen — M1
- \(9.5 - 3.5\) — M1
- 6 — A1
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5 Work out [3 marks]
The side of a square is 20 cm, correct to the nearest 10 cm. [3 marks] (a) Write down the lower bound of the side. [1 mark] (b) Work out the lower bound of the area of the square. [2 marks]
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Model answer
(a) 15 cm. (b) \(15 \times 15 = 225\) cm\(^2\).
Mark scheme
- (a) 15 — B1
- (b) \(15 \times 15\) — M1
- (b) 225 cm\(^2\) — A1
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6 Work out [3 marks]
\(a = 2.4\) and \(b = 1.6\), each correct to 1 decimal place. Work out the upper bound of \(a + b\). [3 marks]
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Model answer
\(2.45 + 1.65 = 4.1\).
Mark scheme
- 2.45 or 1.65 seen — M1
- \(2.45 + 1.65\) — M1
- 4.1 — A1
Quick check
-
1
A length is 12 cm to the nearest cm. What is the error interval?
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A: \(11.5 \leq L < 12.5\)
Half a unit below and above 12, with the lower end included.
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2
\(x = 3.7\) correct to 1 decimal place. What is the error interval?
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D: \(3.65 \leq x < 3.75\)
Half of 0.1 is 0.05, so go from 3.65 up to 3.75.
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3
\(n = 5\) after being truncated to a whole number. What is the error interval?
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C: \(5 \leq n < 6\)
Truncating cuts off the digits, so the number was at least 5 and less than 6.
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4
\(x = 40\) to the nearest 10. What is the error interval?
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B: \(35 \leq x < 45\)
Half of 10 is 5.
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5
Why is the upper bound of an error interval not included?
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A: It would round up to the next value
A value exactly half way rounds up, so it belongs to the next number.
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6
\(x = 0.4\) correct to 1 significant figure. What is the error interval?
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D: \(0.35 \leq x < 0.45\)
The unit is 0.1, so half is 0.05.
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7
What is the upper bound of \(a + b\)?
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C: The upper bound of \(a\) plus the upper bound of \(b\)
The biggest total comes from the biggest values.
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8
What is the upper bound of \(a - b\)?
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B: The upper bound of \(a\) minus the lower bound of \(b\)
To make the difference big, take the biggest \(a\) and subtract the smallest \(b\).
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9
A rectangle is 8 cm by 5 cm, each to the nearest cm. What is the upper bound of its area?
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A: \(46.75\) cm\(^2\)
\(8.5 \times 5.5 = 46.75\).
Recurring Decimals and Rational Numbers
Just this lesson-
1 Write [2 marks]
(a) Write \(\dfrac{7}{20}\) as a decimal. [1 mark] (b) Write \(\dfrac{2}{3}\) as a recurring decimal, using dot notation. [1 mark]
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Model answer
(a) \(7 \div 20 = 0.35\). (b) \(0.\dot{6}\).
Mark scheme
- (a) 0.35 — B1
- (b) \(0.\dot{6}\) — B1
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2 Write [2 marks]
Write \(\dfrac{5}{9}\) as a recurring decimal, using dot notation. [2 marks]
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Model answer
\(5 \div 9 = 0.5555\ldots = 0.\dot{5}\).
Mark scheme
- 0.555 seen — M1
- \(0.\dot{5}\) — A1
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3 Show that [3 marks]
Write \(0.\dot{1}\dot{8}\) as a fraction in its simplest form. [3 marks]
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Model answer
Let \(x = 0.1818\ldots\). Then \(100x = 18.1818\ldots\), so \(99x = 18\) and \(x = \dfrac{18}{99} = \dfrac{2}{11}\).
Mark scheme
- \(100x = 18.1818\ldots\) — M1
- \(99x = 18\) — M1
- \(\dfrac{2}{11}\) — A1
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4 Show that [3 marks]
Write \(0.1\dot{6}\) as a fraction in its simplest form. [3 marks]
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Model answer
Let \(x = 0.1666\ldots\). Then \(100x = 16.666\ldots\) and \(10x = 1.666\ldots\). Subtracting, \(90x = 15\), so \(x = \dfrac{15}{90} = \dfrac{1}{6}\).
Mark scheme
- \(100x\) and \(10x\) seen — M1
- \(90x = 15\) — M1
- \(\dfrac{1}{6}\) — A1
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5 Explain [2 marks]
Here are four numbers: \(\dfrac{22}{7}\), \(\sqrt{25}\), \(\sqrt{11}\) and \(0.\dot{4}\). Which number is irrational? Give a reason. [2 marks]
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Model answer
\(\sqrt{11}\). The others can be written as fractions: \(\dfrac{22}{7}\), \(5\) and \(\dfrac{4}{9}\). \(\sqrt{11}\) is not a perfect square, so it cannot be written as a fraction.
Mark scheme
- \(\sqrt{11}\) — B1
- A correct reason — Q1
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6 Show that [3 marks]
Show that \(0.\dot{5}\dot{4} = \dfrac{6}{11}\). [3 marks]
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Model answer
Let \(x = 0.5454\ldots\). Then \(100x = 54.5454\ldots\), so \(99x = 54\) and \(x = \dfrac{54}{99} = \dfrac{6}{11}\).
Mark scheme
- \(100x = 54.5454\ldots\) — M1
- \(99x = 54\) — M1
- \(\dfrac{54}{99} = \dfrac{6}{11}\) — Q1
Quick check
-
1
What is \(\dfrac{3}{8}\) as a decimal?
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B: 0.375
\(3 \div 8 = 0.375\), which stops.
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2
What is \(\dfrac{1}{3}\) as a recurring decimal?
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A: \(0.\dot{3}\)
The 3 repeats for ever.
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3
What is \(\dfrac{3}{11}\) as a recurring decimal?
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D: \(0.\dot{2}\dot{7}\)
\(3 \div 11 = 0.272727\ldots\), where 27 repeats.
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4
Which fraction gives a terminating decimal?
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C: \(\dfrac{7}{20}\)
\(20 = 2^2 \times 5\), so the decimal 0.35 stops.
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5
Is \(\pi\) rational or irrational?
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B: Irrational
\(\pi\) cannot be written as a fraction.
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6
Is \(\sqrt{16}\) rational or irrational?
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A: Rational, because it equals 4
\(\sqrt{16} = 4 = \dfrac{4}{1}\).
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7
Write \(0.\dot{4}\) as a fraction.
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D: \(\dfrac{4}{9}\)
\(x = 0.\dot{4}\), \(10x = 4.\dot{4}\), so \(9x = 4\).
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8
Write \(0.\dot{4}\dot{5}\) as a fraction in its simplest form.
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C: \(\dfrac{5}{11}\)
\(100x - x = 45\), so \(x = \dfrac{45}{99} = \dfrac{5}{11}\).
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9
Write \(0.1\dot{6}\) as a fraction in its simplest form.
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B: \(\dfrac{1}{6}\)
\(100x - 10x = 15\), so \(x = \dfrac{15}{90} = \dfrac{1}{6}\).