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Scale drawings and bearings - Exam Questions.docx

Built from the lesson script on 30 September 2026.

EDEXCEL GCSE MATHS · FOUNDATION & HIGHER

Exam Practice: Scale Drawings and Bearings

Scale drawings and bearings · Transformations and constructions · Lesson 5 of 8 · 15 marks · 30 minutes

Name

Date

 

Instructions

• Answer all the questions.

• Write your answers in the spaces provided.

• The marks for each question are shown in brackets - use this as a guide to how much to write.

• The answers are on separate pages at the back. Attempt every question before you look at them.

• Answer all questions. Show your working.

Question 1 NON-CALCULATOR (2 marks)

The scale on a map is 1 : 50 000. Two towns are 3.2 cm apart on the map. Work out the real distance between the towns, in kilometres.

(Total for Question 1 = 2 marks)

Question 2 NON-CALCULATOR (2 marks)

Two villages are 4.5 km apart. Work out the distance between them on a map with scale 1 : 25 000. Give your answer in centimetres.

(Total for Question 2 = 2 marks)

Question 3 NON-CALCULATOR (3 marks)

The diagram shows two points, A and B. The bearing of B from A is 072°. Work out the bearing of A from B.

(Total for Question 3 = 3 marks)

Question 4 CALCULATOR (4 marks)

A ship sails 8 km on a bearing of 070°. It then sails 6 km on a bearing of 160°. Work out the distance of the ship from its starting point.

(Total for Question 4 = 4 marks)

Question 5 NON-CALCULATOR (2 marks)

A lighthouse is due south-west of a harbour. Write down the bearing of the lighthouse from the harbour.

(Total for Question 5 = 2 marks)

Question 6 NON-CALCULATOR (2 marks)

The bearing of Q from P is 250°. Work out the bearing of P from Q.

(Total for Question 6 = 2 marks)

TOTAL FOR PAPER = 15 MARKS

 

Answers and mark scheme

Check your answer only once you have written one.

Question 1 (2 marks)

3.2 × 50 000 = 160 000 cm = 1.6 km.

• 3.2 × 50 000 M1

• 1.6 A1

Question 2 (2 marks)

4.5 km = 450 000 cm. 450 000 ÷ 25 000 = 18 cm.

• 450 000 seen M1

• 18 A1

Question 3 (3 marks)

72 + 180 = 252°. The north lines are parallel, so the co-interior angles add up to 180°.

• 180 + 72 or 360 − (180 − 72) M1

• 252 A1

• A reason: parallel lines or back bearing C1

Question 4 (4 marks)

The two bearings differ by 160 − 70 = 90°, so the path forms a right angle. Distance = √(8² + 6²) = √100 = 10 km.

• Right angle found M1

• 8² + 6² M1

• 100 A1

• 10 A1

Question 5 (2 marks)

225°.

• 225 B2

Question 6 (2 marks)

250 − 180 = 070°.

• 250 − 180 M1

• 070 A1