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Combined events - Exam Questions.docx

Built from the lesson script on 30 September 2026.

EDEXCEL GCSE MATHS · FOUNDATION & HIGHER

Exam Practice: Combined Events

Combined events · Probability · Lesson 1 of 6 · 15 marks · 25 minutes

Name

Date

 

Instructions

• Answer all the questions.

• Write your answers in the spaces provided.

• The marks for each question are shown in brackets - use this as a guide to how much to write.

• The answers are on separate pages at the back. Attempt every question before you look at them.

• Answer all questions. Show your working.

Question 1 NON-CALCULATOR (2 marks)

A fair coin is flipped and a fair dice is rolled. Write down the probability of getting a head and a 6.

(Total for Question 1 = 2 marks)

Question 2 NON-CALCULATOR (3 marks)

Two fair dice are rolled and the scores are added. Work out the probability that the total is 7.

(Total for Question 2 = 3 marks)

Question 3 NON-CALCULATOR (3 marks)

Spinner A has three equal sections numbered 1, 2 and 3. Spinner B has four equal sections numbered 1, 2, 3 and 4. Both spinners are spun and the two scores are added. Work out the probability that the total is 5.

(Total for Question 3 = 3 marks)

Question 4 NON-CALCULATOR (2 marks)

For the same two spinners, work out the probability that the total is even.

(Total for Question 4 = 2 marks)

Question 5 NON-CALCULATOR (3 marks)

Two fair dice are rolled and the scores are added. Work out the probability that the total is at least 10.

(Total for Question 5 = 3 marks)

Question 6 NON-CALCULATOR (2 marks)

Two fair dice are rolled. Work out the probability of getting a double (the same number on both dice).

(Total for Question 6 = 2 marks)

TOTAL FOR PAPER = 15 MARKS

 

Answers and mark scheme

Check your answer only once you have written one.

Question 1 (2 marks)

There are 12 equally likely outcomes and one of them is H6. The probability is 1/12.

• 12 outcomes M1

• 1/12 A1

Question 2 (3 marks)

There are 36 equally likely outcomes and 6 give a total of 7. The probability is 6/36 = 1/6.

• 36 outcomes M1

• 6 successful outcomes M1

• 1/6 A1

Question 3 (3 marks)

There are 3 × 4 = 12 outcomes. The totals of 5 are (1, 4), (2, 3) and (3, 2), so the probability is 3/12 = ¼.

• 12 outcomes M1

• Three ways to make 5 M1

• ¼ A1

Question 4 (2 marks)

The even totals come from (1,1), (1,3), (3,1), (3,3), (2,2) and (2,4): 6 of 12. The probability is ½.

• 6 successful outcomes M1

• ½ A1

Question 5 (3 marks)

Totals of 10, 11 and 12 occur 3 + 2 + 1 = 6 times out of 36. The probability is 6/36 = 1/6.

• 6 successful outcomes M1

• 6/36 M1

• 1/6 A1

Question 6 (2 marks)

There are 6 doubles out of 36 outcomes, so the probability is 6/36 = 1/6.

• 6 doubles M1

• 1/6 A1