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The cosine rule and 2D trigonometric problems - Completed Notes.docx

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EDEXCEL GCSE MATHS · HIGHER

The cosine rule and 2D trigonometric problems

More trigonometry · Lesson 6 of 9

Warm-up

Answer each one, then check.

1. What is cos 60°?

0.5

2. What is Pythagoras' theorem?

a² + b² = c²

3. What is the sine rule?

a/(sin A) = b/(sin B)

4. What is a bearing?

An angle measured clockwise from north, with three figures

5. What is cos ⁻¹(0.5)?

60°

Learning Objectives

1. Use the cosine rule to find a missing side.

2. Rearrange the cosine rule to find a missing angle.

3. Decide between the sine rule, cosine rule and right-angled trigonometry.

4. Solve 2D problems, including bearings.

Cosine Rule

The cosine rule links three sides and one angle: it is Pythagoras with a correction.

a² = b² + c² − 2bccos A. To find an angle: cos A = (b² + c² − a²)/2bc.

The Cosine Rule

The angle in the formula is opposite the side you are finding.

A triangle with sides a, b, c and angle A opposite side a, with the cosine rule written underneath.

Which Rule?

USE THE SINE RULE WHEN...

USE THE COSINE RULE WHEN...

▸ You have two angles and a side.

▸ You have two sides and an angle not between them.

▸ You have a matching pair (a side and its opposite angle).

▸ You have two sides and the angle between them.

▸ You have all three sides.

▸ You do not have a matching pair.

Cosine Rule: Finding a Side

In triangle ABC, b = 7 cm, c = 9 cm and angle A = 60°. Find a.

 

1. Write the rule

a² = b² + c² − 2bccos A

2. Substitute

a² = 7² + 9² − 2 × 7 × 9 × cos 60°

3. Work out

a² = 49 + 81 − 63 = 67

4. Square root

a = 8.19

Answer: a = 8.19 cm (3 s.f.)

Cosine Rule: Finding an Angle

A triangle has sides 5 cm, 7 cm and 9 cm. Find the largest angle.

 

1. Largest angle is opposite 9

a = 9, b = 5, c = 7

2. Rearranged rule

cos A = (5² + 7² − 9²)/(2 × 5 × 7)

3. Work out

cos A = (−7)/70 = −0.1

4. Inverse cosine

A = 95.7°

Answer: Largest angle = 95.7° (1 d.p.)

A Bearings Problem

A ship sails 12 km on a bearing of 040° and then 9 km on a bearing of 130°. How far is it from its starting point?

 

1. Angle between the two legs

130°− 40°= 90°

2. Right-angled triangle

Use Pythagoras

3. Work out

12² + 9² = 144 + 81 = 225

4. Square root

√225 = 15

Answer: The ship is 15 km from its start.

Common Slips

Avoid these.

▸ Subtracting before multiplying. Work out 2bccos A as a whole first, then subtract.

▸ Wrong angle. The angle in the formula is opposite the side on the left-hand side.

▸ Rounding early. Keep the full value until the final step.

▸ Angle over 90. A negative cosine means the angle is obtuse; this is fine.

Key Terms

Cosine rule

a² = b² + c² − 2bccos A.

Bearing

A direction measured clockwise from north as three figures.

Included angle

The angle between two given sides.

Obtuse

An angle between 90° and 180°.

Largest angle

The angle opposite the longest side.

Rearrange

Change the subject of a formula.

Your Task: Which Rule and Why?

12 minutes

For each triangle, state which rule you would use first. (a) a = 6, b = 8, C = 50°, find c. (b) a = 5, b = 7, c = 9, find A. (c) A = 40°, B = 70°, a = 8, find b. (d) a = 9, b = 12, A = 30°, find B.

1. Check for a side with its opposite angle.

2. If there is none, use the cosine rule.

A good answer shows: (a) Cosine rule (two sides and the included angle). (b) Cosine rule (three sides). (c) Sine rule. (d) Sine rule.

Can I...?

☐ Write the cosine rule.

☐ Find a missing side.

☐ Rearrange to find an angle.

☐ Identify the largest angle.

☐ Choose sine or cosine rule.

☐ Solve a bearings problem.

☐ Avoid rounding too early.

☐ Check with a sketch.

Summary

✓ a² = b² + c² − 2bccos A.

✓ cos A = (b² + c² − a²)/2bc.

✓ Use cosine rule for SAS and SSS, sine rule when you have a matching pair.

✓ Bearings: measure clockwise from north.

 

EXAM FOCUS

In triangle PQR, PQ = 8.4 cm, PR = 6.1 cm and angle QPR = 57°. Work out the length of QR. Give your answer correct to 3 significant figures. (3 marks)

Write the rule first, substitute, then use your calculator in one go.