AQA GCSE PHYSICS · PAPER 2 · FOUNDATION & HIGHER
Exam Practice: Pressure in a fluid
Pressure in a fluid · Forces · Lesson 7 of 20 · 14 marks · 15 minutes
|
Name |
|
Date |
|
Instructions
• Answer all the questions.
• Write your answers in the spaces provided.
• The marks for each question are shown in brackets - use this as a guide to how much to write.
• The answers are on separate pages at the back. Attempt every question before you look at them.
• Answer all questions. Use the mark allocation as a guide to how much to write.
Question 1 CALCULATE (2 marks)
A person weighs 600 N and stands on an area of 0.04 m². Calculate the pressure on the ground. Use the equation: pressure = force ÷ area
|
|
|
|
|
|
(Total for Question 1 = 2 marks)
Question 2 EXPLAIN (2 marks)
A nail has a sharp point. Explain why it is easier to push into wood than a blunt object.
|
|
|
|
|
|
(Total for Question 2 = 2 marks)
Question 3 EXPLAIN (3 marks)
A tractor with wide tyres does not sink into soft ground as much as a car with narrow tyres of the same weight. Explain why.
|
|
|
|
|
|
|
|
(Total for Question 3 = 3 marks)
Question 4 CALCULATE (3 marks)
A pressure of 2000 Pa acts on a surface of area 0.50 m². Calculate the force on the surface.
|
|
|
|
|
|
|
|
(Total for Question 4 = 3 marks)
Question 5 CALCULATE (4 marks)
A 500 N person wears shoes with a total area of 0.0004 m² on a floor. Calculate the pressure. Then state how many times greater it is than the pressure from flat shoes of area 0.04 m².
|
|
|
|
|
|
|
|
|
|
|
|
(Total for Question 5 = 4 marks)
TOTAL FOR PAPER = 14 MARKS
|
|
Answers and mark scheme
Check your answer only once you have written one.
Question 1 (2 marks)
600 ÷ 0.04 = 15 000 Pa
• Correct substitution 1 mark
• 15 000 Pa 1 mark
Question 2 (2 marks)
The point has a small area, so the same force gives a greater pressure.
• Small area 1 mark
• Greater pressure for the same force 1 mark
Question 3 (3 marks)
The wide tyres spread the weight over a larger area, so the pressure on the ground is smaller.
• Weight is the same 1 mark
• Larger area 1 mark
• Smaller pressure 1 mark
Question 4 (3 marks)
F = pA = 2000 × 0.50 = 1000 N
• Rearranges to F = pA 1 mark
• Correct substitution 1 mark
• 1000 N 1 mark
Question 5 (4 marks)
500 ÷ 0.0004 = 1 250 000 Pa; 500 ÷ 0.04 = 12 500 Pa; the pressure is 100 times greater.
• 1 250 000 Pa 1 mark
• 12 500 Pa 1 mark
• Ratio 100 1 mark
• States 100 times greater 1 mark