EDEXCEL GCSE MATHS · FOUNDATION & HIGHER
Exam Practice: Trigonometry 1
Trigonometry 1 · Angles and trigonometry · Lesson 6 of 7 · 11 marks · 20 minutes
Name Date
Answer all questions. Show your working. You may use a calculator.
Question 1 CALCULATOR [2 marks]
A right-angled triangle has hypotenuse 12 cm. One of its angles is 35°. Work out the length of the side opposite the 35° angle. Give your answer to 3 significant figures.
Question 2 CALCULATOR [3 marks]
Triangle ABC is right-angled at B. AB = 7 cm and angle ACB = 40°. Work out the length of BC. Give your answer to 3 significant figures.
Question 3 CALCULATOR [3 marks]
A right-angled triangle has an angle of 28°. The side adjacent to this angle is 9 cm. Work out the length of the hypotenuse. Give your answer to 1 decimal place.
Question 4 CALCULATOR [3 marks]
Wheelchair ramps must not be too steep. The rules say a ramp must rise no more than 1 m for every 12 m along the ground. A ramp rises at an angle of 5° along 14 m of horizontal ground. Does it meet the rule? Show your working.
Answers
Check your answer only once you have written one.
Question 1 [2 marks]
x = 12 sin 35°= 6.882…= 6.88 cm
▸ sin 35°= x/12 M1
▸ 6.88 A1
Question 2 [3 marks]
From angle C, AB is opposite and BC is adjacent. tan 40°= 7/BC, so BC = 7/(tan 40°) = 8.342…= 8.34 cm
▸ tan 40°= 7/BC M1
▸ BC = 7/(tan 40°) M1
▸ 8.34 A1
Question 3 [3 marks]
cos 28°= 9/h, so h = 9/(cos 28°) = 10.193…= 10.2 cm
▸ cos 28°= 9/h M1
▸ h = 9/(cos 28°) M1
▸ 10.2 A1
Question 4 [3 marks]
Rise = 14 tan 5°= 1.224… m. The rule allows 14 ÷ 12 = 1.166… m. 1.22 > 1.17, so the ramp does not meet the rule.
▸ 14 tan 5° M1
▸ 1.22 and 1.17 (or an equivalent comparison, e.g. tan 5°= 0.087 > 1/12 = 0.083) M1
▸ No, with correct figures C1