Exam questions · Maths · Number Without a Calculator
Powers, Roots and Indices
- 7 exam questions
- 16 marks
- 10 quick checks
-
1 Work out [2 marks]
Work out the value of (a) \(4^3\) (1 mark) (b) \(\sqrt{121}\) (1 mark)
Show answerHide answer
Model answer
(a) \(4 \times 4 \times 4 = 64\). (b) \(\sqrt{121} = 11\) because \(11 \times 11 = 121\).
Mark scheme
- (a) 64 — B1
- (b) 11 — B1
-
2 Simplify [2 marks]
Simplify (a) \(7^4 \times 7^5\) (1 mark) (b) \(3^{10} \div 3^4\) (1 mark)
Show answerHide answer
Model answer
(a) Add the indices: \(7^{4+5} = 7^9\). (b) Subtract the indices: \(3^{10-4} = 3^6\).
Mark scheme
- (a) \(7^9\) — B1
- (b) \(3^6\) — B1
-
3 Work out [3 marks]
(a) Write down the value of \(9^0\). (1 mark) (b) Work out the value of \(5^{-2}\). (2 marks)
Show answerHide answer
Model answer
(a) Any non-zero number to the power 0 is 1, so \(9^0 = 1\). (b) \(5^{-2} = \dfrac{1}{5^2} = \dfrac{1}{25}\).
Mark scheme
- (a) 1 — B1
- (b) \(\dfrac{1}{5^2}\) or \(\dfrac{1}{25}\) — M1
- (b) \(\dfrac{1}{25}\) or 0.04 — A1
-
4 Work out [2 marks]
Work out the value of \(\dfrac{3^5 \times 3^{-2}}{3}\).
Show answerHide answer
Model answer
The top is \(3^{5-2} = 3^3\). Then \(3^3 \div 3^1 = 3^2 = 9\).
Mark scheme
- \(3^3\) for the numerator, or a power of 3 with at most one index error — M1
- 9 — A1
-
5 Simplify [2 marks]
Simplify fully \((2p^3q)^4\).
Show answerHide answer
Model answer
Raise every part to the power 4: \(2^4 \times (p^3)^4 \times q^4 = 16p^{12}q^4\).
Mark scheme
- Any two of \(16\), \(p^{12}\), \(q^4\) correct — M1
- \(16p^{12}q^4\) — A1
-
6 Work out [3 marks]
(a) Work out the value of \(49^{\frac{1}{2}}\). (1 mark) (b) Work out the value of \(8^{-\frac{2}{3}}\). (2 marks)
Show answerHide answer
Model answer
(a) A power of one half means the square root, so \(49^{\frac{1}{2}} = 7\). (b) \(8^{-\frac{2}{3}} = \dfrac{1}{8^{\frac{2}{3}}} = \dfrac{1}{(\sqrt[3]{8})^2} = \dfrac{1}{2^2} = \dfrac{1}{4}\).
Mark scheme
- (a) 7 — B1
- (b) \(\dfrac{1}{8^{2/3}}\) or \(\sqrt[3]{8} = 2\) — M1
- (b) \(\dfrac{1}{4}\) or 0.25 — A1
-
7 Write [2 marks]
Write \(\dfrac{1}{32}\) as a power of 2.
Show answerHide answer
Model answer
\(32 = 2^5\), so \(\dfrac{1}{32} = \dfrac{1}{2^5} = 2^{-5}\).
Mark scheme
- \(32 = 2^5\) or \(\dfrac{1}{2^5}\) — M1
- \(2^{-5}\) — A1
Quick check
-
1
Between which two whole numbers does \(\sqrt{40}\) lie?
Show answerHide answer
A: 6 and 7
\(6^2 = 36\) and \(7^2 = 49\), and 40 is between 36 and 49.
-
2
Write \(16 \times 8\) as a single power of 2.
Show answerHide answer
D: \(2^7\)
\(16 = 2^4\) and \(8 = 2^3\), so \(2^4 \times 2^3 = 2^7\).
-
3
What is the value of \(\sqrt{196}\)?
Show answerHide answer
B: 14
14 × 14 = 196.
-
4
What is the value of \(4^3\)?
Show answerHide answer
C: 64
\(4 \times 4 \times 4 = 64\), not \(4 \times 3 = 12\).
-
5
Simplify \(a^5 \times a^3\).
Show answerHide answer
C: \(a^8\)
Add the indices when multiplying: \(a^{5+3} = a^8\).
-
6
Simplify \((3^2)^4\).
Show answerHide answer
A: \(3^8\)
For a power of a power, multiply the indices: \(3^{2 \times 4} = 3^8\).
-
7
What is the value of \(5^{-2}\)?
Show answerHide answer
B: \(\dfrac{1}{25}\)
A negative index means a reciprocal: \(5^{-2} = \dfrac{1}{5^2} = \dfrac{1}{25}\).
-
8
What is the value of \(7^0\)?
Show answerHide answer
A: 1
Any non-zero number to the power 0 is 1.
-
9
Simplify \(2^6 \div 2^{-2}\).
Show answerHide answer
C: \(2^8\)
Subtract the indices: \(6 - (-2) = 8\), so the answer is \(2^8\).
-
10
What is the value of \(8^{\frac{1}{3}}\)?
Show answerHide answer
D: 2
A power of one third means the cube root, and \(2 \times 2 \times 2 = 8\).