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Lenses - Completed Notes.docx

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AQA GCSE PHYSICS · PAPER 2 · FOUNDATION & HIGHER

Lenses

Waves · Lesson 10 of 12

Warm-up

Answer each one, then check.

1. What is refraction?

A change of direction caused by a change in speed

2. What is a ray?

A line showing the path of light

3. What is an image?

What you see when light from an object is focused

4. What is magnification?

How many times bigger an image is than the object

5. Give an example of a lens use.

Glasses, cameras or magnifying glasses

Learning Objectives

1. Describe how a lens forms an image by refracting light.

2. Define principal focus and focal length for a convex lens.

3. Construct ray diagrams for convex and concave lenses.

4. Distinguish real and virtual images and calculate magnification.

Lenses

A lens forms an image by refracting light. A convex lens brings parallel rays together at the principal focus; a concave lens spreads them out.

Magnification has no units: image height and object height must be in the same units (mm or cm). The magnification equation is given on the Physics equation sheet.

A Convex Lens

Two rays are enough to find the image position.

A ray diagram of a convex lens forming a real, inverted, diminished image of an object beyond 2F.

A Concave Lens

Rays spread out, so the image is virtual.

A ray diagram for a concave lens forming a virtual, upright, smaller image.

Convex and Concave Lenses

Compare them.

Feature

Convex (converging)

Concave (diverging)

Effect on parallel rays

Brings them together at the principal focus

Spreads them out

Image

Real or virtual

Always virtual

Symbol

Vertical line with outward arrowheads

Vertical line with inward arrowheads

Uses

Magnifying glass, camera, projector

Correcting short sight

Magnification

An object is 2.0 cm high. The image formed by a lens is 6.0 cm high. Calculate the magnification.

 

1. Write the equation

magnification = (image height)/(object height)

2. Substitute

6.0/2.0

3. Answer

3.0 (no units)

Answer: Magnification = 3.0

Finding the Image Height

A lens has a magnification of 5. The object is 4 mm high. Calculate the image height.

 

1. Rearrange

image height = magnification × object height

2. Substitute

5 × 4

3. Answer

20 mm

Answer: 20 mm

Real or Virtual?

Explain the difference between a real image and a virtual image.

 

1. Real

Light rays actually meet at the image; it can be shown on a screen

2. Virtual

Rays only appear to come from the image; it cannot be shown on a screen

Answer: A real image can be projected onto a screen; a virtual image cannot.

Drawing Tips

Get full marks.

▸ Use a ruler. Draw straight rays with arrowheads.

▸ Two rays. One parallel to the axis (through F after a convex lens), one through the centre (undeviated).

▸ Mark F. Mark the principal focus on both sides.

▸ Virtual images. Draw the rays as dashed lines behind the lens.

Key Terms

Convex lens

A lens that brings parallel rays to a focus.

Concave lens

A lens that spreads parallel rays out.

Principal focus

The point where parallel rays meet after a convex lens.

Focal length

The distance from the lens to the principal focus.

Real image

An image formed where light rays actually meet.

Virtual image

An image formed where rays appear to come from.

Your Task: Lens Sums

10 minutes

An object of height 3.0 cm gives an image of height 1.2 cm. Calculate the magnification. Is the image bigger or smaller than the object?

1. Use image ÷ object.

2. Compare with 1.

A good answer shows: Magnification = 1.2 ÷ 3.0 = 0.40. The image is smaller (diminished).

Can I...?

☐ Define convex and concave.

☐ Define principal focus.

☐ Define focal length.

☐ Draw a convex lens ray diagram.

☐ Draw a concave lens ray diagram.

☐ Define real and virtual images.

☐ Calculate magnification.

☐ Give a use of each lens.

Summary

✓ Convex: converging; concave: diverging.

✓ Convex images can be real or virtual; concave always virtual.

✓ Magnification = image height ÷ object height (no units).

✓ Two rays to locate the image.

 

EXAM FOCUS

An object is 2.0 cm high. The image is 6.0 cm high. Calculate the magnification. (2 marks)

Image height divided by object height.