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The motor effect - Teacher Notes.docx

The complete notes with the teacher's notes and every model answer in full. Built from the lesson script on 30 September 2026.

AQA GCSE PHYSICS · PAPER 2 · HIGHER TIER ONLY

The motor effect

Magnetism and electromagnetism · Lesson 3 of 8

Teacher copy - includes the notes for whoever is teaching from it.

Warm-up

Answer each one, then check.

1. What is a force?

A push or a pull

2. What is the unit of force?

Newton (N)

3. What is a magnetic field?

A region where a force acts on a magnet

4. What is current?

A flow of charge

5. What is a conductor?

A material that lets current flow

Learning Objectives

1. Explain why a current-carrying wire in a magnetic field experiences a force.

2. Use Fleming's left-hand rule to find the direction of the force.

3. Recall and use F = BIl.

4. State when the force is greatest and when it is zero.

5. Explain how the force can be reversed.

The Motor Effect

force = magnetic flux density × current × length F = BIl

F in newtons (N), B in tesla (T), I in amperes (A) and l in metres (m). The conductor must be at right angles to the field. F = BIl is on the equation sheet.

Fleming's Left-Hand Rule

Thumb: force. First finger: field. Second finger: current.

Fleming's left-hand rule showing the force, field and current directions.

Calculating the Force

A wire of length 0.20 m carries a current of 3.0 A at right angles to a magnetic field of flux density 0.40 T. Calculate the force.

 

1. Write the equation

F = BIl

2. Substitute

F = 0.40 × 3.0 × 0.20

3. Answer

F = 0.24 N

Answer: 0.24 N

Finding the Current

A force of 0.60 N acts on a 0.30 m wire in a field of 0.50 T. Calculate the current.

 

1. Rearrange

I = F ÷ (Bl)

2. Substitute

I = 0.60 ÷ (0.50 × 0.30)

3. Answer

I = 4.0 A

Answer: 4.0 A

Reversing and Changing the Force

Learn what happens.

Change

Effect on the force

Reverse the current

Force reverses

Reverse the magnetic field

Force reverses

Increase the current

Force increases

Stronger magnets (larger B)

Force increases

Wire parallel to the field

No force

Why Does It Happen?

Two magnetic fields.

▸ Two fields. The magnet's field and the field round the wire interact.

▸ Result. The two fields push on each other and the wire feels a force.

▸ Right angles. The force is greatest when the wire is at 90° to the field.

▸ Parallel. No force when the wire is parallel to the field.

Key Terms

Motor effect

The force on a current-carrying conductor in a magnetic field.

Magnetic flux density

A measure of the strength of a magnetic field, in tesla (T).

Tesla

The unit of magnetic flux density.

Fleming's left-hand rule

A rule for finding the direction of the force on a current-carrying wire in a magnetic field.

Conductor

A material that allows a current to flow.

Thumb

Gives the direction of the force in Fleming's left-hand rule.

Your Task: Hand Rule

10 minutes

A current flows left to right through a wire between a north pole (above) and a south pole (below). Use Fleming's left-hand rule. Which way is the force? Then calculate F for B = 0.30 T, I = 5.0 A, l = 0.10 m.

1. Thumb = force.

2. First finger = field.

3. Second finger = current.

A good answer shows: The field points downwards (north to south), the current points to the right, so the force is into the page. F = 0.30 × 5.0 × 0.10 = 0.15 N.

Note: Ask learners to rehearse the rule with their left hand.

Can I...?

☐ State the motor effect.

☐ Use the left-hand rule.

☐ Write F = BIl.

☐ Give units.

☐ Use right angles.

☐ Reverse the force.

☐ Change the force.

☐ Calculate F, I, B or l.

Summary

✓ F = BIl (tesla, amperes, metres).

✓ Left-hand rule: thumb force, first finger field, second finger current.

✓ Reversing current or field reverses the force.

✓ No force if parallel to the field.

 

EXAM FOCUS

A 0.20 m wire carries 3.0 A at right angles to a 0.40 T field. Calculate the force. (2 marks)

F = BIl.

Exam Practice: The motor effect

Answer all questions. Use the mark allocation as a guide to how much to write. · 14 minutes

▸ Question 1 · 2 marks · Calculate. A wire of length 0.20 m carries a current of 3.0 A at right angles to a magnetic field of flux density 0.40 T. Calculate the force on the…

▸ Question 2 · 2 marks · State. State two ways of reversing the direction of the force on a current-carrying wire in a magnetic field.

▸ Question 3 · 3 marks · Calculate. A force of 0.60 N acts on a wire of length 0.30 m in a magnetic field of 0.50 T. The wire is at right angles to the field. Calculate the…

▸ Question 4 · 3 marks · Explain. Explain why a wire carrying a current experiences a force when it is placed between the poles of a magnet.

▸ Question 5 · 3 marks · Explain. Explain what happens to the force on the wire in a magnetic field when the wire is turned so that it is parallel to the field lines. Give a…

Question 1 · 2 marks · Calculate

“A wire of length 0.20 m carries a current of 3.0 A at right angles to a magnetic field of flux density 0.40 T. Calculate the force on the wire. Use the equation: force = magnetic flux density × current × length”

HOW TO ANSWER IT Command word: Calculate. Worth 2 marks, so plan before writing.

Question 1 · mark scheme

2 marks available. Award a mark for each point made.

▸ Correct substitution. 1 mark

▸ 0.24 N. 1 mark

▸ Model answer. F = 0.40 × 3.0 × 0.20 = 0.24 N

Question 2 · 2 marks · State

“State two ways of reversing the direction of the force on a current-carrying wire in a magnetic field.”

HOW TO ANSWER IT Command word: State. Worth 2 marks, so plan before writing.

Question 2 · mark scheme

2 marks available. Award a mark for each point made.

▸ Reverse the current. 1 mark

▸ Reverse the field. 1 mark

▸ Model answer. Reverse the direction of the current. Reverse the direction of the magnetic field (swap the magnets).

Question 3 · 3 marks · Calculate

“A force of 0.60 N acts on a wire of length 0.30 m in a magnetic field of 0.50 T. The wire is at right angles to the field. Calculate the current in the wire.”

HOW TO ANSWER IT Command word: Calculate. Worth 3 marks, so plan before writing.

Question 3 · mark scheme

3 marks available. Award a mark for each point made.

▸ Rearranges to I = F ÷ (B l). 1 mark

▸ Substitution. 1 mark

▸ 4.0 A. 1 mark

▸ Model answer. I = F ÷ (Bl) = 0.60 ÷ (0.50 × 0.30) = 4.0 A

Question 4 · 3 marks · Explain

“Explain why a wire carrying a current experiences a force when it is placed between the poles of a magnet.”

HOW TO ANSWER IT Command word: Explain. Worth 3 marks, so plan before writing.

Question 4 · mark scheme

3 marks available. Award a mark for each point made.

▸ Current produces a magnetic field. 1 mark

▸ Interacts with the magnet's field. 1 mark

▸ Resulting force on the wire. 1 mark

▸ Model answer. The current produces its own magnetic field around the wire. This interacts with the field of the magnet, and the two fields exert a force on each other so the wire moves.

Question 5 · 3 marks · Explain

“Explain what happens to the force on the wire in a magnetic field when the wire is turned so that it is parallel to the field lines. Give a reason.”

HOW TO ANSWER IT Command word: Explain. Worth 3 marks, so plan before writing.

Question 5 · mark scheme

3 marks available. Award a mark for each point made.

▸ Force decreases to zero. 1 mark

▸ Force is greatest at right angles. 1 mark

▸ Fields no longer interact / no component at right angles. 1 mark

▸ Model answer. The force decreases to zero because the wire's field no longer interacts with the magnet's field; the force is largest when the wire is at right angles to the field.