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Maths · Equations and inequalities
Solving linear inequalities
Solve linear inequalities, show solutions on a number line, list integer solutions, and at Higher tier show regions on a graph.
Warm-up
Answer each one, then check.
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1
Solve \(2x + 3 = 11\).
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\(x = 4\)
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2
Solve \(5x = -20\).
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\(x = -4\)
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3
Which is bigger, \(-3\) or \(-5\)?
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\(-3\)
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4
What is the symbol for "less than or equal to"?
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\(\le\)
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5
Solve \(\dfrac{x}{3} = 6\).
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\(x = 18\)
Learning Objectives
- 1Use the inequality symbols \(<\), \(>\), \(\le\) and \(\ge\).
- 2Show inequalities on a number line.
- 3Solve linear inequalities, including reversing the sign.
- 4Write down integer solutions and solve double inequalities.
Inequality Symbols
The open end of the symbol points at the bigger number.
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\(x > 3\)
Meaning: x is greater than 3. Circle on a number line: Open circle at 3
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\(x \ge 3\)
Meaning: x is greater than or equal to 3. Circle on a number line: Filled circle at 3
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\(x < 3\)
Meaning: x is less than 3. Circle on a number line: Open circle at 3
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\(x \le 3\)
Meaning: x is less than or equal to 3. Circle on a number line: Filled circle at 3
Inequalities on a Number Line
Open circle: not included. Filled circle: included.
Solving an Inequality
Solve \(3x + 2 \le 14\).
Show the solutionHide the solution
- 1 Subtract 2 from both sides \(3x \le 12\)
- 2 Divide both sides by 3 \(x \le 4\)
Answer\(x \le 4\)
THE ONE NEW RULE
When you multiply or divide an inequality by a negative number, reverse the inequality sign.
Otherwise solve exactly as you would an equation.
A Negative Coefficient
Solve \(5 - 2x > 11\).
Show the solutionHide the solution
- 1 Subtract 5 from both sides \(-2x > 6\)
- 2 Divide by \(-2\) and reverse the sign \(x < -3\)
- 3 Check with a value, \(x = -4\) \(5 - 2(-4) = 13 > 11\)
Answer\(x < -3\)
A Double Inequality
Solve \(5 < 2x - 1 \le 9\).
Show the solutionHide the solution
- 1 Add 1 to all three parts \(6 < 2x \le 10\)
- 2 Divide all three parts by 2 \(3 < x \le 5\)
Answer\(3 < x \le 5\)
Integer Solutions
List the integers that satisfy \(-2 < x \le 3\).
Show the solutionHide the solution
- 1 \(-2\) itself is not included Start at \(-1\)
- 2 3 is included End at 3
Answer\(-1, 0, 1, 2, 3\)
Shading a Region
Solid line for \(\le\) or \(\ge\), dashed line for \(<\) or \(>\).
Showing an Inequality on a Graph
Draw the boundary, then decide which side to shade.
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1
Draw the line
Replace the inequality sign with = and draw it
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2
Solid or dashed
Solid for \(\le\) and \(\ge\); dashed for \(<\) and \(>\)
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3
Test a point
For example \((0, 0)\), if it is not on the line
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4
Shade the side that works
Shade the wanted region, or the unwanted region, as the question asks
A Region from Three Inequalities
A region R satisfies \(y \ge 1\), \(y \le x\) and \(x + y \le 6\). Find the vertices of R.
Show the solutionHide the solution
- 1 \(y = 1\) meets \(y = x\) \((1, 1)\)
- 2 \(y = 1\) meets \(x + y = 6\) \((5, 1)\)
- 3 \(y = x\) meets \(x + y = 6\) \(x + x = 6\), so \((3, 3)\)
AnswerR is a triangle with vertices \((1, 1)\), \((5, 1)\) and \((3, 3)\).
A Quadratic Inequality
Solve \(x^2 - x - 6 < 0\).
Show the solutionHide the solution
- 1 Factorise \((x - 3)(x + 2) < 0\)
- 2 The roots are \(x = 3\) and \(x = -2\)
- 3 The graph is U-shaped, below the axis between the roots \(-2 < x < 3\)
Answer\(-2 < x < 3\)
True or False?
Decide whether each statement is true or false, and correct it if it is false. (a) \(-3 > -2\) (b) \(x \ge 5\) includes 5 (c) if \(-x < 4\) then \(x < -4\) (d) the integers satisfying \(1 \le x < 4\) are 1, 2, 3, 4.
1. Use a number line.
2. Test values.
A good answer shows: (a) False: \(-3 < -2\). (b) True. (c) False: reversing the sign gives \(x > -4\). (d) False: 4 is not included, so the integers are 1, 2, 3.
Can I...?
- 1Use the four inequality symbols.
- 2Draw an inequality on a number line.
- 3Solve a linear inequality.
- 4Reverse the sign when multiplying by a negative.
- 5Solve a double inequality.
- 6List integer solutions.
- 7Shade a region on a graph (Higher).
- 8Solve a quadratic inequality (Higher).
Summary & Exam Focus
- Open circle for \(<\) and \(>\); filled circle for \(\le\) and \(\ge\).
- Solve like an equation, but reverse the sign when dividing by a negative.
- Double inequality: do the same to all three parts.
- Higher: solid boundary for \(\le\), \(\ge\); dashed for \(<\), \(>\).
Exam focus
Solve \(5 - 2x > 11\). (3 marks) (3 marks)
Dividing by a negative number flips the sign. Check your answer with a test value.
Key terms
The vocabulary this lesson expects you to use. Each one is linked from the first place it appears above.
- Inequality
- A statement that compares two values using \(<\), \(>\), \(\le\) or \(\ge\).
- Integer
- A whole number, positive, negative or zero.
- Solution set
- All the values that make an inequality true.
- Boundary line
- The line that separates a region on a graph.
- Region
- An area of a graph that satisfies one or more inequalities.
- Strict inequality
- One with \(<\) or \(>\), not including the boundary.
Practice questions
Have a go at each one before you open its answer.
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Question 1 Non-calculator 2 marks
Solve \(3x + 2 \le 14\).
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Model answer
\(3x \le 12\), so \(x \le 4\).
Mark scheme
- \(3x \le 12\) — M1
- \(x \le 4\) — A1
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Question 2 Non-calculator 3 marks
Solve \(5 - 2x > 11\).
Show answerHide answer
Model answer
\(-2x > 6\), so \(x < -3\).
Mark scheme
- \(-2x > 6\) — M1
- Dividing by \(-2\) — M1
- \(x < -3\) — A1
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Question 3 Non-calculator 2 marks
The number line shows an inequality. Write down the inequality.
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Model answer
\(-2 < x \le 3\).
Mark scheme
- \(x \le 3\) or \(x > -2\) — B1
- \(-2 < x \le 3\) — B1
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Question 4 Non-calculator 2 marks
\(n\) is an integer. Write down all the possible values of \(n\) when \(-2 < n \le 3\).
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Model answer
\(-1, 0, 1, 2, 3\).
Mark scheme
- At least four correct values — M1
- All correct — A1
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Question 5 Non-calculator 3 marks
Solve \(5 < 2x - 1 \le 9\).
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Model answer
\(6 < 2x \le 10\), so \(3 < x \le 5\).
Mark scheme
- Adding 1 to all parts — M1
- Dividing all parts by 2 — M1
- \(3 < x \le 5\) — A1
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Question 6 Non-calculator 4 marks
On the grid, the region R satisfies \(y \ge 1\), \(y \le x\) and \(x + y \le 6\). Mark the region R with an R.
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Model answer
The lines \(y = 1\), \(y = x\) and \(x + y = 6\) are drawn; the triangle with vertices \((1, 1)\), \((5, 1)\) and \((3, 3)\) is labelled R.
Mark scheme
- One line drawn correctly — M1
- All three lines drawn correctly — M1
- The correct region — M1
- R labelled — A1
Quick check
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Which symbol means "less than or equal to"?
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B: \(\le\)
\(\le\) means less than or equal to.
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Solve \(x + 5 > 8\).
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C: \(x > 3\)
Subtract 5: \(x > 3\).
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Solve \(-3x < 12\).
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D: \(x > -4\)
Divide by \(-3\) and reverse the sign: \(x > -4\).
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Which integers satisfy \(1 \le x < 4\)?
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A: 1, 2, 3
1 is included and 4 is not: 1, 2, 3.
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On a number line, \(x \ge 2\) is shown with...
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B: A filled circle and an arrow right
A filled circle at 2 (included) and an arrow to the right.
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Solve \(x^2 < 9\).
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C: \(-3 < x < 3\)
\(x\) lies between the roots: \(-3 < x < 3\).
Downloads
Free to keep, print and annotate.
- Solving linear inequalities.pptx Built from the lesson script on 30 September 2026. View
- Solving linear inequalities - Completed Notes.docx The full notes for the lesson, to revise from. Built from the lesson script on 30 September 2026. View
- Solving linear inequalities - Exam Questions.docx Built from the lesson script on 30 September 2026. View
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