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Maths · More trigonometry
Transforming trigonometric graphs 2
Transform trigonometric graphs horizontally: translations \(y = f(x + a)\) and stretches \(y = f(ax)\), and find the period and equation from a graph.
Teacher resources
The teacher copies: slides with the questions built in, the answers, and anything else attached to this lesson for whoever is teaching it.
- Transforming trigonometric graphs 2 - Teacher Slides.pptx Teacher The lesson slides with the teacher's notes on each slide, and every question and mark scheme built in. Built from the lesson script on 30 September 2026. View
- Transforming trigonometric graphs 2 - Teacher Notes.docx Teacher The complete notes with the teacher's notes and every model answer in full. Built from the lesson script on 30 September 2026. View
Student handouts
The same files the students see, to print or hand out.
- Transforming trigonometric graphs 2.pptx Built from the lesson script on 30 September 2026. View
- Transforming trigonometric graphs 2 - Completed Notes.docx The full notes for the lesson, to revise from. Built from the lesson script on 30 September 2026. View
- Transforming trigonometric graphs 2 - Exam Questions.docx Built from the lesson script on 30 September 2026. View
Warm-up
Answer each one, then check.
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1
What is the period of \(y = \sin x\)?
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\(360^\circ\)
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2
Where is the first maximum of \(y = \sin x\)?
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\(x = 90^\circ\)
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3
What does \(y = \sin x + 2\) do to the graph?
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Moves it up 2
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4
What is the period of \(y = \tan x\)?
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\(180^\circ\)
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5
What does \(y = 3\sin x\) do to the graph?
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Stretches it vertically by 3
Learning Objectives
- 1Describe and sketch \(y = \sin(x + a)\) and \(y = \cos(x - a)\).
- 2Describe and sketch \(y = \sin ax\) and \(y = \cos ax\).
- 3Find the period of \(y = \sin ax\).
- 4Solve equations such as \(\sin 2x = 0.5\).
HORIZONTAL TRANSFORMATIONS
Changes inside the brackets move or stretch the graph left and right, and often do the opposite of what you expect.
\(y = f(x + a)\) translates left by \(a\). \(y = f(x - a)\) translates right by \(a\). \(y = f(ax)\) stretches horizontally with scale factor \(\dfrac{1}{a}\).
Four Horizontal Transformations
The faint curve is y equals sine x.
Effects on the Graph
Read the change inside the brackets.
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\(y = \sin(x - 30^\circ)\)
Transformation: Translate right 30. Period: \(360^\circ\)
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\(y = \sin(x + 60^\circ)\)
Transformation: Translate left 60. Period: \(360^\circ\)
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\(y = \sin 2x\)
Transformation: Horizontal stretch, scale factor \(\tfrac{1}{2}\). Period: \(180^\circ\)
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\(y = \cos 3x\)
Transformation: Horizontal stretch, scale factor \(\tfrac{1}{3}\). Period: \(120^\circ\)
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\(y = \sin\tfrac{x}{2}\)
Transformation: Horizontal stretch, scale factor 2. Period: \(720^\circ\)
A Horizontal Translation
The graph of \(y = \sin x\) is translated to give \(y = \sin(x + 30^\circ)\). Describe the translation and find the first maximum.
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- 1 Plus inside the bracket Moves left by \(30^\circ\)
- 2 Maximum was at \(90^\circ\)
- 3 Now at \(90^\circ - 30^\circ = 60^\circ\)
AnswerA translation of \(30^\circ\) to the left; the first maximum is at \(x = 60^\circ\).
A Horizontal Stretch
State the period of \(y = \cos 3x\) and how many full waves there are between \(0^\circ\) and \(360^\circ\).
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- 1 Period \(\dfrac{360^\circ}{3} = 120^\circ\)
- 2 Number of waves \(\dfrac{360}{120} = 3\)
AnswerThe period is \(120^\circ\), giving 3 full waves.
Solving sin 2x = 0.5
Solve \(\sin 2x = 0.5\) for \(0^\circ \le x \le 360^\circ\).
Show the solutionHide the solution
- 1 Range for \(2x\) \(0^\circ \le 2x \le 720^\circ\)
- 2 Solve for \(2x\) \(2x = 30^\circ,\ 150^\circ,\ 390^\circ,\ 510^\circ\)
- 3 Halve \(x = 15^\circ,\ 75^\circ,\ 195^\circ,\ 255^\circ\)
Answer\(x = 15^\circ,\ 75^\circ,\ 195^\circ,\ 255^\circ\)
Inside and Outside the Brackets
Outside the brackets: vertical
- \(y = a\sin x\): stretch in y.
- \(y = \sin x + a\): translate up.
- Does what it looks like.
Inside the brackets: horizontal
- \(y = \sin(x + a)\): translate left.
- \(y = \sin ax\): stretch in x by \(\tfrac{1}{a}\).
- Does the opposite of what it looks like.
Period Detective
State the period of each graph. (a) \(y = \sin 4x\) (b) \(y = \cos\tfrac{x}{3}\) (c) \(y = \tan 2x\). Then say where the first maximum of (a) is.
1. Divide the normal period by the number.
2. Divide the first maximum position in the same way.
A good answer shows: (a) \(90^\circ\). (b) \(1080^\circ\). (c) \(90^\circ\) (tangent's normal period is \(180^\circ\), so divide by 2). First maximum of (a) at \(x = 22.5^\circ\).
Can I...?
- 1Describe y = sin(x + a).
- 2Describe y = sin(x - a).
- 3Describe y = sin ax.
- 4Find the period.
- 5Find a first maximum.
- 6Sketch a transformed graph.
- 7Solve sin 2x = k.
- 8Find a from a graph.
Summary & Exam Focus
- \(y = f(x + a)\): translate left by \(a\). \(y = f(x - a)\): translate right.
- \(y = f(ax)\): stretch in x by scale factor \(\tfrac{1}{a}\).
- Period of \(\sin ax\) or \(\cos ax\): \(\dfrac{360^\circ}{a}\).
- Solving \(\sin ax = k\): extend the range to \(360a\).
Exam focus
Solve \(\sin 2x = 0.5\) for \(0^\circ \le x \le 360^\circ\). (4 marks) (4 marks)
Find the range for the whole bracket first. Then solve, then divide.
Key terms
The vocabulary this lesson expects you to use. Each one is linked from the first place it appears above.
- Period
- The length after which the graph repeats.
- Horizontal stretch
- A stretch that changes the x-values.
- Translation
- A slide left, right, up or down.
- Scale factor
- The number the x-values are multiplied by.
- Full wave
- One complete cycle of the graph.
- Phase shift
- A horizontal translation of a trig graph.
Questions and answers
12 questions set on this lesson, with the mark schemes and model answers open.
The graph shows \(y = \cos ax\) for \(0^\circ \le x \le 360^\circ\), where \(a\) is a positive whole number. Find the value of \(a\).
Mark scheme — 2 marks available
- Three waves or period \(120^\circ\) — M1
- 3 — A1
Model answer
\(a = 3\)
Describe the single transformation that maps the graph of \(y = \sin x\) onto the graph of \(y = \sin(x - 40^\circ)\).
Mark scheme — 2 marks available
- Translation — M1
- \(40^\circ\) to the right — A1
Model answer
A translation of \(40^\circ\) to the right, that is by the vector \(\begin{pmatrix}40 \\ 0\end{pmatrix}\).
Write down the period of \(y = \sin 4x\).
Mark scheme — 1 mark available
- 90 — B1
Model answer
\(90^\circ\)
Write down the coordinates of the first maximum point of \(y = \sin(x - 30^\circ)\) for \(x > 0\).
Mark scheme — 2 marks available
- \(x = 120\) — B1
- \(y = 1\) — B1
Model answer
\((120^\circ, 1)\)
On a grid, sketch the graph of \(y = \sin 2x\) for \(0^\circ \le x \le 360^\circ\).
Mark scheme — 3 marks available
- Two full waves — B1
- Maximum 1 and minimum \(-1\) — B1
- Correct roots or turning points — B1
Model answer
Two full sine waves: maxima of 1 at \(45^\circ\) and \(225^\circ\), minima of \(-1\) at \(135^\circ\) and \(315^\circ\), crossing the x-axis at \(0^\circ, 90^\circ, 180^\circ, 270^\circ, 360^\circ\).
Solve \(\sin 2x = 0.5\) for \(0^\circ \le x \le 360^\circ\).
Mark scheme — 4 marks available
- \(2x = 30\) — M1
- \(2x = 150\) — M1
- Extends to \(390\) and \(510\) — M1
- All four answers — A1
Model answer
\(x = 15^\circ,\ 75^\circ,\ 195^\circ,\ 255^\circ\)
\(y = \sin(x + 20^\circ)\) is a translation of \(y = \sin x\)...
Why: A plus inside the brackets moves the graph left.
The period of \(y = \cos 2x\) is...
Why: \(360 \div 2 = 180\).
\(y = \sin\tfrac{x}{2}\) has period...
Why: \(360 \div \tfrac{1}{2} = 720\).
How many full waves does \(y = \sin 3x\) have for \(0 \le x \le 360\)?
Why: The period is 120, so there are 3 full waves.
The first maximum of \(y = \sin(x - 50^\circ)\) is at...
Why: \(90 + 50 = 140\).
To solve \(\sin 2x = 0.5\) for \(0 \le x \le 360\), the range for \(2x\) is...
Why: Double the range: 0 to 720.